A 34N force is applied to a 213kg mass. How much does the mass accelerate?

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Answer 1 · 2018-03-24T05:53:00

#~~0.16 \ "m/s"^2#

We use Newton's second law of motion, which states that,

#F=ma#

#m# is the mass of the object in kilograms

#a# is the acceleration of the object in meters per second

We need to solve for acceleration, so we rearrange the equation into,

#a=F/m#

Now, we just need to plug in our given values, and we get,

#a=(34 \ "N")/(213 \ "kg")#

#~~0.16 \ "m/s"^2#

Answer 2 · 2018-03-24T10:25:34

#0.16m//s^2#

Using Newton's second law that states Force #(N)#=Mass (#Kg)# x Acceleration #(m//s^2)#

We can re-arrange this to get Acceleration #(m//s^2)#=Force #(N)# / Mass#(Kg)#

The Force here is #34N# and the mass is #213kg#:

#therefore# A=#34/213=0.15962441...m//s^2#

Rounding (If appropriate), if not leave it as the full answer...

#-> 0.16m//s^2#