A 35 kg child moves with uniform circular motion while riding a horse on a carousel. The horse is 3.2 m from the carousel's axis of rotation and has a tangential speed of 2.6 m/s. what is the child's centripetal acceleration?

1 Answer
Nov 29, 2017

The child's centripetal acceleration is 2.1125m \/s^2.

Explanation:

Newton's second law relates force F, mass m and acceleration a.

F=ma

The centripetal force required to keep an object of mass m with tangential velocity v at a radius r is:

F=(mv^2)/r

Combining these two equations gives:

ma=(mv^2)/r

Mass m is a factor of both sides and cancels out.

a=v^2/r

In the case of the child v=2.6 and r=3.2. So the centripetal acceleration a is:

a=2.6^2/3.2=2.1125