A 350-mL solution contains 12.6 g NaCl. What is the molarity of the solution?

Jun 20, 2016

The molarity of the solution is 0.617 M.

Explanation:

Let's use this equation:

Okay, so we have a bit of work to do! The volume is given in terms of mL and we have to convert that to L by using the following conversion factor: $1 L = 1000 m L$

350cancel"mL"xx(1L)/(1000cancel"mL") = 0.350L

Now we have to express NaCl in terms of moles. We can do this by using the molar mass of NaCl (58.44 g/mol) as a conversion factor.

$12.6 \cancel{g} \times \frac{1 m o l}{58.44 g} = 0.216 m o l$

Now we can divide the moles by the volume to obtain the molarity like this:

$M o l a r i t y = \frac{0.216 m o l}{0.350 L}$

M =0.617