Question

A 350-mL solution contains 12.6 g `NaCl`. What is the molarity of the solution?

Answer 1

The molarity of the solution is 0.617 M.

Explanation:

Let's use this equation:

Okay, so we have a bit of work to do! The volume is given in terms of mL and we have to convert that to L by using the following conversion factor: `1L = 1000mL`

`350cancel"mL"xx(1L)/(1000cancel"mL") = 0.350L`

Now we have to express NaCl in terms of moles. We can do this by using the molar mass of NaCl (58.44 g/mol) as a conversion factor.

`12.6 cancelgxx(1mol)/(58.44g) = 0.216mol`

Now we can divide the moles by the volume to obtain the molarity like this:

`Molarity = (0.216mol)/(0.350L)`

M =0.617