A 4.78-g sample of aluminum completely reacts with oxygen to form 6.67 g of aluminum oxide. What is the mass percent composition of aluminum in aluminum oxide?

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Answer 1 · 2015-10-30T22:44:14

#71.7%#

The percent composition of aluminium in the

resulting oxide will be the ratio between the mass of aluminijm and the total mass of the oxide, multiplied

by #100#.

#"% Al" = m_"Al"/m_"oxide" xx 100#

In your case, you know that a #"4.78-g"# sample of aluminium reacts completely with excess oxygen to form an

unknown aluminium oxide.

Moreover, you know that this oxide has a mass of #"6.67 g"#.

Since all the luminium that initially reacted with the oxygen is now a part of the oxide, you can say that its

percent composition in the oxide will be

#"% Al" = (4.78color(red)(cancel(color(black)("g"))))/(6.67color(red)(cancel(color(black)("g")))) xx 100 = 71.664%#

Rounded to three sig figs, the

answer will be

#"% Al" = color(green)(71.7%)#