A #4 L# container holds #4 # mol and #4 # mol of gasses A and B, respectively. Groups of four of molecules of gas B bind to three molecule of gas A and the reaction changes the temperature from #280^oK# to #320^oK#. By how much does the pressure change?

1 Answer
Apr 19, 2017

#10 atm#

Explanation:

First, you need to turn the information into a chemical equation:
#3A(g) + 4B(g) -> A_3B_4(g)#

Then you find the moles of product formed and moles of reactant left. You should get 1 mol of #A_3B_4(g)# and 1 mol #A(g)# left.

After that you just input the information into the formula #P_(Total) = (n_(Total)RT)/V#

#P_(Total) = (2mols * 0.08206 "L atm " mol^-1 K^-1 * 320 K)/(4L)#
#P_(Total) = 13.1296atm#

Since you only have one significant figure, the answer would be #10 atm#.