A 445 g sample of ice at -58°C is heated until its temperature reaches -29°C. What is the change in heat content of the system?
The change in heat content is
Use the following equation:
Insert your data into the equation and solve.
Very cold, no phase change. So, the heat change is just the amount of heat absorbed by the ice to raise its temperature by 29 degrees. The specific heat of ice is 2.100 J/g-’C.
The temperature change is
The enthalpy change is thus 445g * (29’C) * 2.10 J/g-’C = 271000 Joules, (27.1 kJ).