A 45.0 mL sample of water is heated from 15.0°C to 35.0°C. How many joules of energy have been absorbed by the water?

1 Answer
Aug 22, 2017

Answer:

We need the specific heat of water in #J*g^-1*""^@C^-1#. These data should have been supplied with the question.

Explanation:

Now #C_p#, #"specific heat of water"#, is #4.18*J*g^-1*""^@C^-1#. We have the mass of water, and we have #DeltaT=20.0*""^@C#.

And so we solve the product.......

#"Mass of water"xxC_pxxDeltaT#

#45.0*mL*xx1*g*mL^-1xx4.18*J*g^-1*""^@C^-1xx20.0*""^@C#

#~=4000*J#