Question

A 5.00 L container contains `CH_4` at 35°C with a total pressure of 1.81 atm. What is the pressure of the gas when it expands to 25.0 L at 25°C?

Answer 1

`(P_1V_1)/T_1=(P_2V_2)/T_2` `~=` `0.4*atm`

Explanation:

`(P_1V_1)/T_1=(P_2V_2)/T_2`

`P_2=(P_1V_1)/T_1xxT_2/V_2`

`=(1.81*atmxx5.00*Lxx298*K)/(308*Kxx25.0*L)` `=` `??atm`

Note that I used absolute temperature, as these problems always require such readings: