# A 50.0 g sample of an unknown substance absorbed 1.64 kJ of energy as it changed from a temperature of 36°C to 98°C. What is the specific heat of the unknown substance in J/g°C?

##### 1 Answer

May 20, 2018

#### Explanation:

Specific heat of a substance is given by the formula

#"S" = "Q"/"mΔT"#