A 60 g piece of metal at an initial temperature of 92°C is transferred into 70 g of water initially at 24.5°C. The final temperature of the water and the metal is 40°C. How do you determine the specific heat of the metal?

Question

Assume perfect heat transfer.

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Answer 1 · 2017-03-16T17:43:57

#(-1.45362J)/(gram C^o)#

#q_"gain" = q_"lost"#

#(60g)(92^o - 40^oC)(x) = (70g)(24.5^oC - 40^oC)(4.18)"#

4.18 is specific of water. Solve for x

#3120x=-4535.3#

#x = 4535.3/3120 or 45353/31200#

#x = -1.45362#