Question

A 9 V battery is connected to a bulb whose resistance is 3000 ohms. How many electrons leave the battery per minute?

Answer 1

`1.125 xx 10^18` electrons leave the battery per minute.

Explanation:

`I = V/R`

`I = (9V)/(3000 Ω)`

`I = 3 xx 10^-3 A`

`I = (nQ)/t`

`n = (It)/Q`

`n = (3 xx 10^-3 A xx 60 s) / (1.6 xx 10^-19 C)`

`n = 1.125 xx 10^18`