# A bag has 9 red marbles and 6 green marbles. How do you find the probability of drawing a green marble, replacing it, and drawing another green marble?

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Hihi Share
Feb 25, 2018

$\frac{4}{25}$

#### Explanation:

First, we have the probability of drawing a green marble as 6 out of (6+9), which is $\frac{6}{15}$.

After that, we replace the green marble into the bag. At this moment, the bag becomes the same as it is before a green marble is drawn, i.e. there are still 6 green marbles and 9 red ones.
If we are too draw another green marble, the same probability, $\frac{6}{15}$, will be resulted.

As both requirements have to be fulfilled, the required probability is the multiplication of both,
$= \frac{6}{15} \cdot \frac{6}{15}$

$= \frac{36}{225}$

$= \frac{4}{25}$

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