# A balanced lever has two weights on it, one with mass 2 kg and one with mass 16 kg. If the first weight is  8 m from the fulcrum, how far is the second weight from the fulcrum?

Dec 11, 2015

$1 \text{m}$

#### Explanation:

You can use the principle of moments. The moment of a force is the force multiplied by the perpendicular distance of the force from the fulcrum.

For the lever to be balanced the anti - clockwise moments must balance the clockwise moments.

So from the diagram we can write:

$2 g \times 8 = 16 g \times d$

$\therefore d = \frac{16 g}{16 g} = 1 \text{m}$