A balanced lever has two weights on it, the first with mass 1 kg  and the second with mass 5 kg. If the first weight is  2 m from the fulcrum, how far is the second weight from the fulcrum?

Apr 25, 2018

The distance is $= 0.4 m$

Explanation:

The mass ${M}_{1} = 1 k g$

The mass ${M}_{2} = 5 k g$

The distance $a = 2 m$

${M}_{1} \times a = {M}_{2} \times b$
$b = \frac{{M}_{1} \times a}{{M}_{2}} = \frac{1 \times 2}{5} = 0.4 m$