# A balanced lever has two weights on it, the first with mass 15 kg  and the second with mass 9 kg. If the first weight is  4 m from the fulcrum, how far is the second weight from the fulcrum?

Dec 9, 2016

The distance is $= 6.67 m$

#### Explanation:

The moments on both sides of the fulcrum must de equal on equilibrium.

$M o m e n t =$Force x distance

So,

Moment of first weight $= 15 g \cdot 4 = 60 g N m$

Moment of the second weight $= 9 g \cdot d N m$

Where $d =$ distance from the fulcum

On equilibrium

$60 g = 9 g \cdot d$

$d = \frac{60}{9} = \frac{20}{3} = 6.67 m$