# A balanced lever has two weights on it, the first with mass 15 kg  and the second with mass 27 kg. If the first weight is  8 m from the fulcrum, how far is the second weight from the fulcrum?

Feb 15, 2016

$x = \frac{40}{9} m$
$\text{(the first mass) X (distance from fulcrum)=(the second mass) X (distance from fulcrum)}$
$15 \cdot 8 = 27 \cdot x$
$x = \frac{120}{27}$
$x = \frac{40}{9} m$