A balanced lever has two weights on it, the first with mass $15 kg$ and the second with mass $27 kg$ . If the first weight is $8 m$ from the fulcrum, how far is the second weight from the fulcrum?

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Answer 1 · 2016-02-15T09:44:24

$x=40/9 m$

$"(the first mass) X (distance from fulcrum)=(the second mass) X (distance from fulcrum)"$
$15*8=27*x$
$x=120/27$
$x=40/9 m$

A balanced lever has two weights on it, the first with mass 15 kg 15 kg and the second with mass 27 kg27 kg. If the first weight is 8 m 8 m from the fulcrum, how far is the second weight from the fulcrum?