A balanced lever has two weights on it, the first with mass 15 kg  and the second with mass 18 kg. If the first weight is  6 m from the fulcrum, how far is the second weight from the fulcrum?

Apr 11, 2017

The distance is $= 5 m$

Explanation:

Here, we have

${M}_{2} = 15 g N$

$b = 6 m$

${M}_{1} = 18 g N$

Taking moments about the fulcrum

$15 g \cdot 6 = 18 g \cdot a$

$a = \frac{15 \cdot 6}{18} = 5 m$