A balanced lever has two weights on it, the first with mass 15 kg  and the second with mass 18 kg. If the first weight is  9 m from the fulcrum, how far is the second weight from the fulcrum?

1 Answer
Apr 3, 2018

$7.5$ meters

Explanation:

For a balanced lever, we have:

${m}_{1} {d}_{1} = {m}_{2} {d}_{2}$

• ${m}_{1} , {m}_{2}$ are the masses of the two objects

• ${d}_{1} , {d}_{2}$ are the distances of the two objects from the fulcrum

And so, we got:

$15 \setminus \text{kg"*9 \ "m"=18 \ "kg} \cdot {d}_{2}$

${d}_{2} = \left(135 \textcolor{red}{\cancel{\textcolor{b l a c k}{\text{kg""m")/(18color(red)cancelcolor(black)"kg}}}}\right)$

$= 7.5 \setminus \text{m}$