A balanced lever has two weights on it, the first with mass 15 kg  and the second with mass 24 kg. If the first weight is  7 m from the fulcrum, how far is the second weight from the fulcrum?

May 31, 2016

4.375m

Explanation:

Since the two weights kept on the lever balance it.The moments of the weihgts about the fulcrum
will be equal.

The weight of the mass 15kg is 15gN and that of 24kg is 24gN.
The first is weight is 7m away
from fulcrum.If the second is xm
away from the fulcrum then we can write

$x \times 24 g = 7 \times 15 g$
$x = \frac{7 \cdot 15}{24} = 4.375 m$