# A balanced lever has two weights on it, the first with mass 27 kg  and the second with mass 18 kg. If the first weight is  3 m from the fulcrum, how far is the second weight from the fulcrum?

Mar 29, 2017

The distance is $= 4.5 m$

#### Explanation:

${M}_{2} = 18 g N$

$a = 3 m$

${M}_{1} = 27 g N$

${M}_{1} \cdot a = {M}_{2} \cdot b$
$27 g \cdot 3 = 18 g \cdot b$
$b = \frac{27 g \cdot 3}{18 g}$
$= 4.5 m$