# A balanced lever has two weights on it, the first with mass 3 kg  and the second with mass 4 kg. If the first weight is  5 m from the fulcrum, how far is the second weight from the fulcrum?

Mar 25, 2016

$3 \frac{3}{4}$ meters

#### Explanation:

Let $x$ be the distance the second weight is from the fulcrum.

Since the lever is balanced
$\textcolor{w h i t e}{\text{XXX}} 3 k g \times 5 m = 4 k g \times x$

$\rightarrow \textcolor{w h i t e}{\text{XXX}} x = \frac{3 \cancel{k g} \times 5 m}{4 \cancel{k g}} = 3 \frac{3}{4} m$