A balanced lever has two weights on it, the first with mass 3 kg  and the second with mass 27 kg. If the first weight is  6 m from the fulcrum, how far is the second weight from the fulcrum?

Nov 30, 2017

The distance is $= \frac{2}{3} m$

Explanation:

The masses are

${M}_{1} = 27 k g$

and

${M}_{2} = 3 k g$

The distance $b = 6 m$

${M}_{1} \times a = {M}_{2} \times b$
$27 \times a = 3 \times 6$
$a = \frac{3 \times 6}{27} = \frac{2}{3} m$