# A balanced lever has two weights on it, the first with mass 3 kg  and the second with mass 7 kg. If the first weight is  8 m from the fulcrum, how far is the second weight from the fulcrum?

Apr 19, 2017

The distance is $= 3.43 m$

#### Explanation:

Mass, ${M}_{2} = 3 k g$

Mass, ${M}_{1} = 7 k g$

Distance, $b = 8 m$

${M}_{1} \cdot a = {M}_{2} \cdot b$
$a = {M}_{2} / {M}_{1} \cdot b$
$= \frac{3 g}{7 g} \cdot 8 = \frac{24}{7} m$