A balanced lever has two weights on it, the first with mass #4 kg # and the second with mass #6 kg#. If the first weight is # 8 m# from the fulcrum, how far is the second weight from the fulcrum?

1 Answer
Apr 3, 2016

Answer:

The equation is #F_Lxxd_L=F_Rxxd_R#
Where #F=#force, #d=#distance, #L=#left, #R=right#

Explanation:

When we translate the masses into forces, we have the constant #g# on both sides, so they cancel. The equation then turns into:
#m_Lxxcancelgxxd_L=m_Rxxcancelgxxd_R#

#4kgxx8m=6kgxxd_R#

#d_R=(4cancel(kg)xx8m)/(6cancel(kg))=32/6m=5 1/3m#