A balanced lever has two weights on it, the first with mass 4 kg  and the second with mass 1 kg. If the first weight is  8 m from the fulcrum, how far is the second weight from the fulcrum?

Jun 3, 2017

The distance is $= 32 m$

Explanation:

The first weight is ${M}_{1} = 4 g N$

The second weight is ${M}_{2} = 1 g N$

The distance $a = 8 m$

$4 g \cdot 8 = 1 g \cdot b$
$b = 32 \frac{g}{g} = 32 m$
The distance is $= 32 m$