# A balanced lever has two weights on it, the first with mass 6 kg  and the second with mass 7 kg. If the first weight is  5 m from the fulcrum, how far is the second weight from the fulcrum?

Feb 25, 2017

The distance is $= 4.28 m$

#### Explanation:

The load $L = 6 g N$

The distance of the load from the fulcrum is $= 5 m$

The effort is $E = 7 g N$

The distance of the effort to the fulcrum is $x m$

In a situation of equilibrium, the moments are equal

So,

$6 \cdot 5 = 7 \cdot x$

$x = \frac{30}{7} = 4.28 m$