A balanced lever has two weights on it, the first with mass 8 kg  and the second with mass 24 kg. If the first weight is  6 m from the fulcrum, how far is the second weight from the fulcrum?

Jul 9, 2016

$x = 2 \text{ } m$

Explanation:

${F}_{1} \cdot \overline{A B} = {F}_{2} \cdot \overline{B C}$

${F}_{1} \cdot 8 = x \cdot {F}_{2}$

$x = \frac{8 \cdot {F}_{1}}{F} _ 2$

$\text{plug "F_1=6*g" ; } {F}_{2} = 24 \cdot g$

$x = \frac{8 \cdot 6 \cdot \cancel{g}}{24 \cdot \cancel{g}}$

$x = \frac{48}{24}$

$x = 2 \text{ } m$