A ball is rolling down a hill at #+2.0# #m##/##s#. The ball is uniformly accelerating at #+4.0# #m##/##s^2#. What will the ball's velocity be #3.0# #s# later?

1 Answer
Jane
Mar 2, 2018

Well considering that the net acceleration of the ball is #+4 ms^-2# downwards,we can apply the equation #v=u+at# ,where #v# is the velocity of the ball after time #t#,which had an initial velocity of #u# and moving with constant acceleration #a#

Given, #u=2,a=4,t=3#

So,#v=2+4*3=14 ms^-1#

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