A ball is shot from cannnon into air with upward velocity of 40 ft/sec. The equation that gives the height(h) of the ball at any time id h(t)= -16t^2+40t+1.5. How many seconds rounded to the nearest hundreth will it take the ball to reach the ground?

1 Answer
Mar 13, 2018

2.56s

Explanation:

Given equation is h=-16t^2 +40t+1.5

Put,t=0 in the equation,you will get,h=1.5 that means,the ball was shot from 1.5 ft above the ground.

So,when after going upto a maximum height (let,x),it reaches the ground,its net displacement will be x-(x+1.5)=-1.5ft(as upward direction is taken positive as per the equation given)

So,if it takes time t then,putting h=-1.5 in the given equation,we get,

-1.5=-16t^2 +40t+1.5

Solving this we get,

t=2.56s