# A ball is thrown into the air from the roof of the building. Its height (in feet) t seconds later is given by h(t)=80+80t-16t^2. What is the initial height of the ball?

$80$ ft.
At time $t = 0$ (the initial time)
$\textcolor{w h i t e}{\text{XXX}} h \left(0\right) = 80 + 80 \left(0\right) - 16 {\left(0\right)}^{2} = 80$ feet