# A ball is thrown vertically with an initial velocity of #64# feet per second. Its height above the ground after #t# seconds is given by #h(t) = 64t—16t^2#. What is the maximum height?

##### 1 Answer

Nov 17, 2015

I found

#### Explanation:

Ok...probably you can do this differently but I would try to find the **vertex** of the parabola describing the trajectory:

1) derive it:

2) set derivative equal to zero:

3) use this value of

Graphically: