A ball with a mass of #280 g# is projected vertically by a spring loaded contraption. The spring in the contraption has a spring constant of #12 (kg)/s^2# and was compressed by #7/3 m# when the ball was released. How high will the ball go?

1 Answer
Jun 20, 2016

#"spring constant "(k)=12"kg"/s^2#
#"compressed length "(x)=7/3m#
Potential energy of spring=#1/2kx^2#

#"Mass of the ball "(m)=280g=0.28kg#

By principle of conservation of energy

Energy of spring=energy of the ball

#1/2*k*x^2=mgh#
#=>h=1/2(kx^2)/(mg)#
#=>h=1/2*12*(7/3*7/3)*1/(0.28*9.8)#
#=>h=1/(3*0.028)=11.9m#