A ball with a mass of #280 g# is projected vertically by a spring loaded contraption. The spring in the contraption has a spring constant of #42 (kg)/s^2# and was compressed by #5/3 m# when the ball was released. How high will the ball go?

1 Answer
Apr 12, 2016

Answer:

#h=21,25" m"#

Explanation:

#"given data:"#

#Delta x=5/3 m#

#K=42 (kg)/s^2#

#m=280g=0,28 kg" mass of object"#

#g=9,81 m/s^2#

#h=?#

#E_p=1/2*k*Delta x^2" Potential energy for compressed springs"#

#E=m*g*h " potential energy for object raising from earth"#

#E_p=E" conservation of energy"#

#m*g*h=1/2*K*Delta x^2#

#h=(K*Delta x^2)/(2*m*g)#

#h=(42*(5/3)^2)/(2*0,28*9,81)#

#h=(42*25/9)/(5,49)#

#h=(116,67)/(5,49)#

#h=21,25" m"#