A ball with a mass of #450 g# is projected vertically by a spring loaded contraption. The spring in the contraption has a spring constant of #12 (kg)/s^2# and was compressed by #4/5 m# when the ball was released. How high will the ball go?

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Answer 1 · 2016-07-05T09:23:06

#h = 128/(15 g)#[m]

Calling

#h# height attained
#m = 0.450# ball mass
#K=12# spring constant
#Delta x = 4/5# compressed length

Equating potential energies

#m g h = 1/2K (Delta x)^2#

then

#h = 1/2 K/(mg) (Deltax)^2 = 128/(15 g)#