A ball with a mass of #8 kg# moving at #7 m/s# hits a still ball with a mass of #13 kg#. If the first ball stops moving, how fast is the second ball moving?

Question

1319 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-04-04T12:02:38

The velocity of the second ball after the collision is #=4.31ms^-1#

#m_1u_1+m_2u_2=m_1v_1+m_2v_2#

The mass the first ball is #m_1=8kg#

The velocity of the first ball before the collision is #u_1=7ms^-1#

The mass of the second ball is #m_2=13kg#

The velocity of the second ball before the collision is #u_2=0ms^-1#

The velocity of the first ball after the collision is #v_1=0ms^-1#

Therefore,

#8*7+13*0=8*0+13*v_2#

#13v_2=56#

#v_2=56/13=4.31ms^-1#

The velocity of the second ball after the collision is #v_2=4.31ms^-1#