A ball with a mass of #80 g# is projected vertically by a spring loaded contraption. The spring in the contraption has a spring constant of #14 (kg)/s^2# and was compressed by #1/5 m# when the ball was released. How high will the ball go?

1 Answer
Apr 17, 2016

Answer:

#h=0,36" "m#

Explanation:

#E_p:" the potential energy for the compressed spring"#
#k=14(kg)/s^2" spring constant"#
#Delta x=1/5 m#

#E_p=1/2*k*Delta x^2#

#E_p=1/2*14*(1/5)^2#

#E_p=7*1/25#

#E_p=0,28J#

#m=80g=0,08 kg" mass of object"#

g=9,81 N/(kg)

#E_g=m*g*h" the gravitational potential energy"#

#E_g=0,08*9,81*h#

#E_g=0,78*h#

#E_p=E_g#

#0,28=0,78*h#

#h=0,28/0,78#

#h=0,36" "m#