# A balloon has a volume of 2.9 L at 320 Kelvin. If the temperature is raised to 343 Kelvin, what will its volume be?

Feb 4, 2017

$3.1084375 L$

#### Explanation:

Use unitary method

We could use the gas laws if we were given other information like moles of gas and pressure but since we dont have them we can use unitary method

So this question can be represented as

$\text{2.9L" / "320K} \cdot 343 K = 3.1084375 L$

Now we know the volume so let us find Pressure
using the gas law $P V = n R T$

$V = \frac{\text{(nRT)}}{P}$

$3.1084375 L = \frac{\text{(n * 0.0821 * 343K)}}{P}$

P = "28.1603n"/{3.1084375