A baseball goes from zero to 41 m/s in 0.238 s. What is its average acceleration?

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Answer 1 · 2017-09-21T14:17:23

average acceleration of the baseball is #172.269ms^-2#

Acceleration of baseball is the change in velocity in a given interval of time divided by the time taken.

#a=(v_2-v_1)/t#.

where,

#v_1# is the initial velocity,

#v_2# is the final velocity and

#t# is the time taken (or the time interval in which velocity changes from initial velocity to the final velocity)

Therefore ,
#v_1=0ms^-1#.
#v_2=41ms^-1 #.

#t=0.238s#

SUBSTITUTING THE VALUES IN THE EQUATION :

#a=(41-0)/0.238ms^-2#
#a=172.269ms^-2#

Here we are provided with the initial and final velocity only so that acceleration we find is the average acceleration of the baseball .