A beaker contains 0.32 L of water. What is the volume of this in milliliters?

1 Answer
May 15, 2017

Answer:

#320*mL#

Explanation:

The #"milli"# prefix #-=# #10^-3#. And thus #1*mL# #-=# #10^-3*L#.

And so #0.32*L-=0.32*cancel(L)xx10^3*mL*cancel(L^-1)=320*mL.#

Sometimes (especially in Old Blighty), we use the #"cubic decimeter"# to represent #1*L#. How? Well there are #1000*L# in a #"cubic meter"#, a rather large volume, that is certainly no good as a unit of measurement in a lab.........

But #1*dm^3=(1xx10^-1*m)^3=10^-3*m^3=1*L# as required.........