Question

A beaker contains 0.32 L of water. What is the volume of this in milliliters?

Answer 1

`320*mL`

Explanation:

The `"milli"` prefix `-=` `10^-3`. And thus `1*mL` `-=` `10^-3*L`.

And so `0.32*L-=0.32*cancel(L)xx10^3*mL*cancel(L^-1)=320*mL.`

Sometimes (especially in Old Blighty), we use the `"cubic decimeter"` to represent `1*L`. How? Well there are `1000*L` in a `"cubic meter"`, a rather large volume, that is certainly no good as a unit of measurement in a lab.........

But `1*dm^3=(1xx10^-1*m)^3=10^-3*m^3=1*L` as required.........