A beaker contains oil of density 0.8 g/cm^3. By means of a thread, a 1.6 cm cube of aluminum(p=2.7g/cm^3) is submerged in the pil. Find the tension in the thread?

1 Answer
Apr 18, 2018

The tension is #=76.27*10^-3N#

Explanation:

Volume of the cube of aluminium is

#V=1.6^3=4.096cm^3#

Mass of the cube of aluminium is

#m=v*rho=4.096*2.7=11.0592g#

Mass of oil displaced by the cube is

#m_d=v*rho_(oil)=4.096*0.8=3.2768g#

The tension in the string is

#T=mg-m_d#

#=11.0592*10^-3*9.8-3.2768*10^-3*9.8#

#=7.7824*9.8*10^-3#

#=76.27*10^-3N#