Question

A block of wood floats in water with 2/3 of its volume submerged. Its relative density is?

Answer 1

`0.67 g/(cm^3)`

Explanation:

Let,the density of the block be `d`

Now,as it floats in water with its `2/3 rd` submerged,it means, its weight is being balanced by the buoyant force of water on the 2/3rd of its total volume.

So,from equation of force,we can write,

`v*d*g = 2/3 v*1*g` (as,density of water is `1 g/(cm^3)`)

So, `d=2/3=0.67`