Question

A body of mass 10kg moving with a constant velocity of 10m/s.when a constant force acts for 4sec on it .it moves with velocity 2m/s in opposite direction the acceleration produced is ?

Answer 1

The acceleration is

`a = (Deltav)/(Deltat)`

I shall assign a negative sign to the final velocity:

`v_2 = -2" m/s"`

And a positive sign to the initial velocity:

`v_1 = 10" m/s"`

`Deltav = v_2 - v_1`

`Deltav = -2" m/s" - 10" m/s"`

`Deltav = -12" m/s"`

We are given `Deltat = 4" s"`

`a = (-12" m/s")/(4" s")`

`a = -3" m/s"^2`