A body with uniform acceleration travel distance 12m in the third second and 20metre in fifth second.find the velocity after 10th second?

1 Answer
Jun 10, 2017

42ms^-1

Explanation:

Here a formula,
S=u+1/2a(2n-1) where S is displacement,u= initial velocity
and n=time
1_(st) case,
12=u+(5a)/2=>24=2u+5a
Similarly,
40=2u+9a
From both equations, a=4ms^-2
u=2ms^-1
In 10_th sec the velocity of the body is u+at=2+(4×10)=42ms^-1