Question

A bottle of calcium bromide contains a bromide ion concentration of 0.10 mol/L. What is the concentration of the calcium bromide?

Answer 1

`[CaBr_2]=0.050*mol*L^-1`

Explanation:

Calcium bromide speciates in aqueous solution according to the following equation.........

`CaBr_2(s) stackrel(H_2O)rarrCa^(2+) + 2Br^-`

And thus for every metal ion there are necessarily two bromide ions.

Here by specification,

`[Br^-]=0.10*mol*L^-1`, and thus `[Ca^(2+)]=1/2xx[Br^-]=1/2xx0.10*mol*L^-1=0.050*mol*L^-1`