A bullet of mass 10gm is fired with a rifle . The bullet takes 0.003sec. to move through its barrel and leaves with a velocity of 300m/sec . What is the force exerted on the bullet by the rifle?

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Answer 1 · 2018-06-21T11:52:09

The force is #=1000N#

The impulse due to the force is equal to the change in momentum

#Ft=mDeltav#

The time is #t=0.003s#

The mass of the bullet is #m=10g=0.01kg#

The change in velocity of the bullet is #Deltav=300ms^-1#

The force is

#F=(mDeltav)/t=(0.01*300)/0.003=1000N#