A calorimeter has 195 g of water at 20.4°C. A 37.8 g sample of an unknown metal is heated to 133°C and placed in the water in the calorimeter. Heat flows from the metal to the water until the final temperature of the water and the metal stabilizes?

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Question not finished. 24.6°C. What is the specific heat of the metal

The formula is q=mcp and change in temp. (Idk how to type in the trangle shape, but its that with a capital T next to it).
q= heat energy
M= specific heat
/\T= change in temperature

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Answer 1 · 2018-04-10T00:09:14

#c= 0.836 J/(g°C)#

If no hear is lost to the surroundings then the heat lost by the metal must equal to the heat gained by the water:
#Q=-Q#

And since:
#Q=mcDeltat#

#mcDeltat=-mcDeltat#

#(195 g)(4.184 J/(g°C))(24.6°C-20.4°C)= -(37.8 g)(c)(24.6°C-133°C)#

#3426.696 J= (4097.52 g°C)*c

#c= 0.836 J/(g°C)#