A car drives straight off the edge of a cliff that is 58 m high. The police at the scene of the accident note that the point of impact is 0.136 km from the base of the cliff. How far from the cliff was the car after 1.5s?

Question

826 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2015-11-05T21:55:10

#59.3"m"#

We can find the time of flight by considering the vertical component of the motion:

#s=1/2"g"t^2#

#t^2=(2s)/"g"#

#t=sqrt((2xx58)/(9.8))#

#t=3.44"s"#

The horizontal component of velocity is constant so:

#v=s/t=136/3.44=39.53"m/s"#

So after 1.5s we get:

#s=vxxt=39.53xx1.5=59.3"m"#