# A car is traveling at 50 mi/h when the brakes are fully applied, producing a constant deceleration of 32 ft/s2. What is the distance covered before the car comes to a stop? (Round your answer to one decimal place.)?

Oct 21, 2016

$84.0 f t$, rounded to one decimal place

#### Explanation:

Applicable Kinematic equation is
${v}^{2} - {u}^{2} = 2 a s$
where $v , u , a \mathmr{and} s$ are final velocity, initial velocity, deceleration and distance covered respectively.

Now, $50 m p h \times \frac{1760 \times 3}{3600} = 73.3333 f p s$
Inserting given and calculated values

${0}^{2} - {73.3333}^{2} = 2 \left(- 32\right) s$
$\implies s = {73.3333}^{2} / 64$
$s = 84.0 f t$, rounded to one decimal place