Question

A car traveling initially at 5.37 m/s accelerates at the rate of 0.639 m/s 2 for 5.94 s. What is its velocity at the end of the acceleration? Answer in units of m/s.

Answer 1

For constant acceleration `a` acting for a time `t` we have the kinematic expression

`v=u+at`
where `u` is initial velocity and `v` is the final velocity.

Inserting given values we get
`v=5.37+0.639xx5.94`
`v=5.37+3.796`
`v=9.17" m s"^-1`, rounded to two decimal places.