A cat pushes a ball from a 7.00 m high window, giving it a horizontal velocity of 0.20 m/s. How far from the base of the building does the ball land?

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Answer 1 · 2018-01-26T19:12:43

The ball lands 0.239 m from the base of the building.

First, we find how long it takes to fall 7.00 m.

#s = u*t + 1/2*a*t^2#

#7.00 m = 0*t + 1/2*9.8 m/s^2*t^2#

#2*7.00 m = 9.8 m/s^2*t^2#

#t^2 = (14.00 m)/(9.8 m/s^2) = 1.429 s^2#

#t = sqrt(1.429 s^2) = 1.195 s#

How far does the horizontal velocity of 0.20 m/s carry it during those 1.195 s?

#s = v*t = 0.20 m/s * 1.195 s = 0.239 m#

I hope this helps,
Steve